SOLUTION: assume the random variable X is normally distributed with mean u=50 and standard deviation o=7. find the 96th percentile

SOLUTION: assume the random variable X is normally distributed with mean u=50 and standard deviation o=7. find the 96th percentile

Algebra.Com

Question 998974: assume the random variable X is normally distributed with mean u=50 and standard deviation o=7. find the 96th percentile
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
z(0.96)=+1.751
That is the number of standard deviations from the mean
12.257 units from the mean, or 62.257 is the 96th percentile.
RELATED QUESTIONS
Assume the random variable X is normally distributed with mean 50 and standard deviation... (answered by Boreal)

assume that the random variable X is normally distributed, with mean m = 50 and standard... (answered by ewatrrr)

assume that the random variable X is normally distributed, with mean m = 50 and standard... (answered by stanbon)

Assume the random variable x is normally distributed with mean u=50 and standard... (answered by ewatrrr)

Assume the random variable X is normally distributed with mean μ equals=50 and... (answered by Fombitz)

Assume the random variable X is normally distributed with mean muequals50 and standard... (answered by Boreal)

assume the random variable x is normally distributed with mean u=50 and standard... (answered by oscargut)

Assume that the random variable X is normally distributed with a mean of 70 and a... (answered by rothauserc)

Assume the random variable X is normally distributed with mean μ = 60 and standard... (answered by Boreal)