SOLUTION: Suppose that 2.8% of the people in a city are infected with a particular virus. If 80 people from the city are selected at random, what is the probability that at least one of them
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Question 988039: Suppose that 2.8% of the people in a city are infected with a particular virus. If 80 people from the city are selected at random, what is the probability that at least one of them is infected? Round your answer to three decimal places.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Suppose that 2.8% of the people in a city are infected with a particular virus. If 80 people from the city are selected at random, what is the probability that at least one of them is infected? Round your answer to three decimal places.
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Binomial Problem with n = 80 and p(infected) = 0.028
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P(at least one) = 1 - P(none of the 80 are infected)
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P(at least one) = 1 - (0.972)^80 = 0.8969
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Cheers,
Stan H.
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