SOLUTION: Nine playing cards are laid out on a table. They are all Clubs numbered from 2 to 10. The cards are shuffled, cut, shuffled and cut one last time. You select one card, what is
Algebra.Com
Question 979867: Nine playing cards are laid out on a table. They are all Clubs numbered from 2 to 10. The cards are shuffled, cut, shuffled and cut one last time. You select one card, what is the probability that you select:
an odd numbered card? a card that is a multiple of 3? the 6 of Clubs? NOT the 10 of Clubs?
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
Total number of cards = 9
Total number of odd numbered cards = 4
Probability of selecting an odd numbered
card = 4/9
Total number of cards that are a multiple
of 3 = 3
Probability of selecting a card that is
a multiple of 3 = 3/9 or 1/3
The probability of selecting the
6 of clubs = 1/9
The probability of not selecting
the 10 of clubs = 8/9
Hope this helps:-)
RELATED QUESTIONS
Suppose that 7 cards are drawn from a well shuffled deck of 52 cards. What is the... (answered by Mathtut)
A game uses 26 playing cards. Playing cards have four suits - diamonds (♢), clubs... (answered by Edwin McCravy)
Cards numbered 1-10 are shuffled and dealt face down. What is the the probability that... (answered by ewatrrr)
If five cards are dealt from a shuffled deck of playing cards (52 cards), what is the... (answered by Alan3354)
A gambler is dealt the following hand from a randomly shuffled normal 52 card deck: the... (answered by stanbon)
A player draws one card from a special deck of 27 playing cards shown here. The deck,... (answered by solver91311)
You are dealt two cards successively (without replacement) from a shuffled deck of 52... (answered by stanbon)
You are dealt two cards successively (without replacement) from a shuffled deck of 52... (answered by stanbon)
you are dealt two cards successively (without replacement) from a shuffled deck of 52... (answered by Fombitz,ewatrrr)