SOLUTION: A large population based study estimated that 65% of Australian children regular eat fruit In a random sample of 70 Australian children, what is the probability of at least 50 reg

Question 974947: A large population based study estimated that 65% of Australian children regular eat fruit
In a random sample of 70 Australian children, what is the probability of at least 50 regularly eat fruit?

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
mean is 65%
1 sample proportion z-test;
phat-0.65/sqrt[[(0.65)*(0.35)/70}; phat = 0.714
z=(0.714-0.65)/.0570
z=+1.123 the probability that 50 or LESS will. This is 0.870
The probability that at least 50 will is 0.130.
This makes intuitive sense. The expected value if 45.5, so the likelihood of at least 50 in a sample will is less than half.
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