SOLUTION: what is the probability that at least 5 of the 25 students trying out for the baseball team are left-handed if 11% of the population is left-handed ?

Question 972924: what is the probability that at least 5 of the 25 students trying out for the baseball team are left-handed if 11% of the population is left-handed ?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
p .11
q = 1-.11 = .89
m = n*.11 = 2.75
s = sqrt(n*p*q) = sqrt(25*.11*.89) = sqrt(2.4475) = 1.56
z = (5 - 2.75) / 1.56 = 1.44
p(z >= 1.44) = .0749
the probability that 5 or more of the team members will be left handed is 7.49%.
p = probability of success = .11
q = probability of failure = .89
m = mean = 2.75
s = standard error of the mean = 1.56
z = z-score = (x-m)/s = (5 - 2.75)/1.56
x = raw score of 5

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