SOLUTION: A researcher wishes to estimate the proportion of left-handers among a certain population. In a random sample of 900 people from the population, 74% are left-handed. Find the margi
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Question 971846: A researcher wishes to estimate the proportion of left-handers among a certain population. In a random sample of 900 people from the population, 74% are left-handed. Find the margin of error for the 95% confidence interval.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
1 sample proportion test CI
=p +/- z*SE
SE=sqrt{(.74)(.26)/900}
numerator is 0.74
SE=0.0146
95 % CI has z= +/-1.96
z*SE=.029
95% CI= 0.74 +/- 0.029 [0.711,0.769]
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