SOLUTION: P(C)= 0.2 P(B)= 0.3 And Events are Mutually Exclusive.. Find P(BuC')'..

Question 965984: P(C)= 0.2
P(B)= 0.3
And Events are Mutually Exclusive..
Find P(BuC')'..
Answer by tenkun(12) (Show Source): You can put this solution on YOUR website!
P(C)= 0.2
P(B)= 0.3
P(C') = 1-P(C)= 0.8
P(B intersection C')= P(B)*P(C')
=0.3*0.8
= 0.24
P(BuC')= P(B)+P(C')-P(B intersection C')
= 0.3+0.8-0.24
=0.86
P(BuC')'=1 -P(BuC')
=1-0.86
=0.14

RELATED QUESTIONS
If A and B are mutually exclusive events with P(A) = 0.75, then... (answered by MathLover1,ikleyn)

U and V are mutually exclusive events. P(U)=0.55, P(V)=0.32, find P(U and V) (answered by ikleyn)

E and F are mutually exclusive events. P(E) = 0.15; P(F) = 0.71. Find P(E | F) (answered by ikleyn)

Suppose P(A) = 0.25 and P(B) =0.15.If A and B are independent events but not mutually... (answered by ikleyn)

U and V are mutually exclusive events. P(U)=0.41 ; P(V)=0.51 find: P(UAND V) find: P(U... (answered by ikleyn)

You are given the probabilities below: P(a) = 0.25 P(B) = 0.30 P(C) = 0.55 P(A and C) (answered by robertb,jim_thompson5910)

You are given the following: P(A)=0.25 P(B)=0.30 P(C)=0.55 P(A and C)=0.05 P(B and (answered by Edwin McCravy)

Given that p(A)= 1/4 p(B)= 1/5 p(C)= 1/2 Compute the following 1)... (answered by MathLover1)

Suppose events A and B are such that P(A) = .4 and P(B) =.3. If A and B are mutually... (answered by fractalier)