SOLUTION: For the following hypothesis test, A) state the null and alternative hypotheses, B) determine the critical value(s) that define the rejection region, C) calculate the value of the

Question 958535: For the following hypothesis test, A) state the null and alternative hypotheses, B) determine the critical value(s) that define the rejection region, C) calculate the value of the test statistic, D) make the decision to reject the null hypothesis or not, E) state a full conclusion, a sentence in the context of the given problem.
The National Highway Traffic Safety Administration conducted crash tests, with the measurements given in hic. The safety requirement is that the hic measurement should be less than 1000 hic. Use a 0.01 significance level to test the claim that the sample is from a population with a mean less than 1000 hic.
774 649 1210 546 431 612
Please help - more than confused - completely besides myself. Please help. Thank you.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The National Highway Traffic Safety Administration conducted crash tests, with the measurements given in hic. The safety requirement is that the hic measurement should be less than 1000 hic. Use a 0.01 significance level to test the claim that the sample is from a population with a mean less than 1000 hic.
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CORRECTED VERSION::
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774 649 1210 546 431 612
sample mean = 703.67
s = 272.73
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A) state the null and alternative hypotheses,
Ho:: u >= 1000
Ha:: u < 1000 (claim)
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B) determine the critical value(s) that define the rejection region,
Find the t-value with a 1% left tail with 5 degrees of freedom.
t = invt(0.01,5) = -3.365
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C) calculate the value of the test statistic,
t(703.67) = (703.67-1000)/[272.73/sqrt(6) = -2.66
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D) make the decision to reject the null hypothesis or not,
Since the test statistic is not in the reject interval, fail to
reject Ho at the 1% level of significance.
______________

E) state a full conclusion, a sentence in the context of the given problem.
The test results do not support the claim that the mean is less than 1000.
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Sorry for the error on the critical value.
Senior moment I guess.
Cheers,
Stan H.
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