SOLUTION: A person's phone requires 5 digit password. How many passwords are possible if the 4th digit must be an odd number and the 5th digit must be an even number?

SOLUTION: A person's phone requires 5 digit password. How many passwords are possible if the 4th digit must be an odd number and the 5th digit must be an even number?

Algebra.Com

Question 955368: A person's phone requires 5 digit password. How many passwords are possible if the 4th digit must be an odd number and the 5th digit must be an even number?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
even digits are: 0,2,4,6, and 8
odd digits are: 1,3,5,7,and 9
1st digit: possible
2nd digit: possible
3rd digit: possible
4th digit: possible
5th digit: possible
------------------------
Possible passwords =

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