SOLUTION: Probability P (A or B), P (A and B) there are M&M candies in a jar: Red (7), Blue (7) and Yellow (7). a) probability that randomly taken one candy is blue or red: P (Blue or Red

Question 943753: Probability P (A or B), P (A and B) there are M&M candies in a jar: Red (7), Blue (7) and Yellow (7). a) probability that randomly taken one candy is blue or red: P (Blue or Red) b) probability that out of 2 candies randomly taken from the jar first candy will be Red and second candy will be Red again: P(Red and then Red). Keep in mind that in case b), after you take the first candy, there will be one less candies in the box.
Counting Outcomes (Permutations and Combinations) For numbers 8 and 2, in how many ways can you select 2 items out of 8 if order of selection makes a difference - use Permutations b) in how many ways can you select 2 items out of 8 if order of selection doesn't matter - use Combinations.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Probability P (A or B), P (A and B)
there are M&M candies in a jar: Red (7), Blue (7) and Yellow (7).
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a) probability that randomly taken one candy is blue or red:
P (Blue or Red) = P(blue) + P(red) = 7/21 + 7/21 = 14/21 = 2/3
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b) probability that out of 2 candies randomly taken from the jar first candy will be Red and second candy will be Red again:
P(Red and then Red) = P(red)*P(red|red) = (7/21)(6/20) = (1/3)(3/10) = 1/10
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Counting Outcomes (Permutations and Combinations) For numbers 8 and 2, in how many ways can you select 2 items out of 8 if order of selection makes a difference - use Permutations
8P2 = 8*7 = 56
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b) in how many ways can you select 2 items out of 8 if order of selection doesn't matter - use Combinations.
8C2 = (8*7)/(1*2) = 28
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Cheers,
Stan H.
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