SOLUTION: A set of normally distributed data has a mean of 3.2 and a standard deviation of 0.7. Find the probability of randomly selecting 30 values and getting a mean greater than 3.6.

Question 941685: A set of normally distributed data has a mean of 3.2 and a standard deviation of 0.7. Find the probability of randomly selecting 30 values and getting a mean greater than 3.6.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A set of normally distributed data has a mean of 3.2 and a standard deviation of 0.7. Find the probability of randomly selecting 30 values and getting a mean greater than 3.6.
-------
Note: Standard deviation for the mean of the sample means = s/sqrt(n)
-------
Your Problem::
z(3.6) = (3.6-3.2)/[0.7/sqrt(30)] = 0.4*sqrt(30)/0.7 = 3.1300
---
P(x-bar > 3.6) = normalcdf(3.13,100) = 0.0008750
===============
Cheers,
Stan H.
RELATED QUESTIONS
a set of normally distributed data has a mean of 47 and standard deviation of 0.6.. find... (answered by stanbon)

A normally distributed data set of 500 values has a mean of 35 and a standard deviation... (answered by Boreal)

In a normally distributed data set what percentage of data points lie between mean +-... (answered by ewatrrr)

A set of data that is normally distributed has a mean of 35.6 and a Standard deviation of (answered by stanbon)

Suppose you have data that is normally distributed with a mean of 36 and a standard... (answered by stanbon)

A set of normally distributed data has mean 47 s and standard deviation 0.6 s. Find the... (answered by stanbon)

A set of data with a mean of 28 and a standard deviation of 4.2 is normally distributed. (answered by solver91311)

A set of data with a mean of 58 and a standard deviation of 6.3 is normally distributed. (answered by jim_thompson5910)

A set of data items is normally distributed with a mean of 80 and a standard deviation of (answered by ewatrrr)