SOLUTION: There are two red sweets and seven green sweets in a bag. Two sweets are taken at random, one at a time, from the bag (the first sweet is not put back in the bag). Find the probab

Question 936013: There are two red sweets and seven green sweets in a bag. Two sweets are taken at random, one at a time, from the bag (the first sweet is not put back in the bag).
Find the probability that the sweets will be
(A) both red. (B) of different colours. (C) the same colour
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
A)
Solution:
P(both red) = (2/9)(1/8) = 1/36
Answer: 1/36
B)
Solution:
P(of different colors) = P(R,G)+P(G,R) = (2/9)(7/8)+(7/9)(2/8) = 7/18
Answer: 7/18

C)
Solution:
P(same colours) = 1-P(different colours) = 1-7/18 = 11/18
Answer: 11/18
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