SOLUTION: Suppose that the scores of architects on a particular creativity test are normally distributed. Using a normal curve table, what percentage of architects have Z scores: Above .1

Question 933627: Suppose that the scores of architects on a particular creativity test are normally distributed. Using a normal curve table, what percentage of architects have Z scores:
Above .10?
Below .10?
Above .20?
Below .20?
Above 1.10?
Below 1.10?
Above -.10?
Below -.10?

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Above .10 = 1 - .5398
Below .10 = .5398 = normalcdf(-100, .10)
......
Above .20 = 1 - .5793
Below .20 = .5793 = normalcdf(-100, .20)
......
Above 1.10 = 1-.8643
Below 1.10= .8643 = normalcdf(-100, 1.10)
......
Above -.10 = 1 - .4602
Below -.10 = .4602 = = normalcdf(-100, -.10)
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