SOLUTION: A container has 7 slips of paper numbered 1, 2, 3, 4, 5, 6, 7. Two different slips of paper are chosen at random from these seven slips. Find the probability that (a) both slips

Question 932423: A container has 7 slips of paper numbered 1, 2, 3, 4, 5, 6, 7. Two different slips of paper are chosen at random from these seven slips. Find the probability that (a) both slips contain an odd number (b) add to 9
How do you do this problem?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
slips of paper numbered 1, 2, 3, 4, 5, 6, 7
4Odd. 3 Even
2 slips add to nine: 2,7 & 3,6 & 4,5
.......
2 drawn (w/o replacement: 7C2 = 21 possible pairs
P(both odd) =
P(add to 9) = 3/21 = 1/7
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