SOLUTION: On a test, the raw scores have a mean of 35 and a standard deviation of 6. Assuming these raw scores form a normal distribution... a.) what number represents the 65th percentile?

Question 932319: On a test, the raw scores have a mean of 35 and a standard deviation of 6. Assuming these raw scores form a normal distribution...
a.) what number represents the 65th percentile?
b.) what number represents the 90th percentile?
c) what is the probability of getting a raw score between 28 and 38?
d) What is the probability of getting a raw score between 41 and 44?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
mean of 35 and a standard deviation of 6.
.....
Using a TI calculator 0r similarly a Casio fx-115 ES plus
P( 28 P(41 < x < 44) = P( 6/6 < z < 9/6)= normalcdf(1, 1.5)= .0918
.......
65th percentile: 6(invNorm(.65)) + 35 = 6( .3853) + 35 = x = 38 (using next Integer)
90th percentile: 6(invNorm(.90)) + 35 = 6 (1.2816) + 35 = x

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