SOLUTION: A normal population has a mean of 66 and a standard deviation of 4. You select a sample of 48.
Compute the probability the sample mean is: (Round z values to 2 decimal place
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Question 931785: A normal population has a mean of 66 and a standard deviation of 4. You select a sample of 48.
Compute the probability the sample mean is: (Round z values to 2 decimal places and final answers to 4 decimal places.)
(a) Less than 65.
Probability
(b) Between 65 and 67.
Probability
(c) Between 67 and 68.
Probability
(d) Greater than 68.
Probability
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
mean of 66 and a standard deviation of 4.
n = 48,
P(x < 65) = P(z <-1/.58) = normalcdf(-100, -1.72)
P(65 < x <67) = P(-1.72 < z < 1.72) = normalcdf(-1.72, 1.72)
P( 67< x < 68) = P(1.72 < z < 3.45)=normalcdf(1.72, 3.45)
P(x > 68) = P(z > 3.45) = normalcdf(3.45, 100)
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