SOLUTION: If 10% of a population of parts is defective, what is the probability of randomly selecting 90 parts and finding that 14 or more parts are defective?
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Question 924511: If 10% of a population of parts is defective, what is the probability of randomly selecting 90 parts and finding that 14 or more parts are defective?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
p(def) = .10, n = 90
Using a TI calculator 0r similarly a Casio fx-115 ES plus
p(x > 14) = 1 - binomcdf(90, .10, 14) = 1- .9667 = .0333 0r 3.33%
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