SOLUTION: let x have a normal distribution with mean of 24 and standard deviation of 6 find the probability that an x value selected at random from this distribution is between 30 and 33
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Question 924110: let x have a normal distribution with mean of 24 and standard deviation of 6 find the probability that an x value selected at random from this distribution is between 30 and 33
I have to show all work
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
mean of 24 and standard deviation of 6:
P(30 < x < 33) = P( 6/6 < z < 9/6) = normalcdf(1, 1.5) = .0918
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