SOLUTION: I have the hardest problem getting the last step of this problem. I get .4675 but it keeps saying that is wrong. Any help, please?
If A and B are independent events, P(A) = 0.45
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Question 921515: I have the hardest problem getting the last step of this problem. I get .4675 but it keeps saying that is wrong. Any help, please?
If A and B are independent events, P(A) = 0.45, and P(B) = 0.15, find the probabilities below. (Enter your answers to four decimal places.)
(a) P(A ∩ B)
.675
(b) P(A ∪ B)
.5325
(c) P(A | B)
.4500
(d) P(Ac ∪ Bc)
Incorrect: Your answer is incorrect.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I have the hardest problem getting the last step of this problem. I get .4675 but it keeps saying that is wrong. Any help, please?
If A and B are independent events, P(A) = 0.45, and P(B) = 0.15, find the probabilities below. (Enter your answers to four decimal places.)
(a) P(A ∩ B) = P(A)*P(B) = 0.45*0.15 = 0.0675
-------------------
(b) P(A ∪ B) = P(A)+P(B)-P(A and B) = 0.45+0.15-0.0675 = 0.5325
--------------------
(c) P(A | B) = P(A and B)/P(B) = 0.0675/0.15 = 0.45
===============================
(d) P(Ac ∪ Bc)
P(Ac) = 0.55 ; P(Bc) = 0.85
--
P(Ac U Bc) = P(Ac)+P(Bc) - P(Ac and Bc) = 0.55 + 0.85 - [1-P(Ac OR Bc)]
---
= 1.4 -1 - 2P(Ac OR Bc)
-----
2P(Ac OR Bc) = 0.4
P(Ac OR Bc) = 0.2
------------------------
Cheers,
Stan H.
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