SOLUTION: Use the normal distribution of fish lengths for which the mean is 10 inches and the standard deviation is 4 inches. Assume the variable x is normally distributed. What percent of t

Question 916503: Use the normal distribution of fish lengths for which the mean is 10 inches and the standard deviation is 4 inches. Assume the variable x is normally distributed. What percent of the fish are longer than 14 inches? If 200 fish are randomly selected, about how many would you expect to be shorter than 6 inches?

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi

mean = 10, SD = 4

P(x > 14) = P( z > 1) = normalcdf(1, 100) = 15.87%

  = 4/4 = 1

.......

Sample 200..assuming the large sample has normal distribution

P(x < 6)  = P(z <  -1) = 15.87% 

200(.1587) = 32 rounded UP

......

Area under the standard normal curve to the left of the particular z is P(z)

Note: z = 0 (represents the mean) 50% of the area under the curve is to the left and 50%  to the right



 

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