SOLUTION: Please help with this question. In a survey of 200 randomly selected teenagers, 60% indicated that they have drunk alcoholic beverages in the past. The margin of error for this

Question 916291: Please help with this question.
In a survey of 200 randomly selected teenagers, 60% indicated that they have drunk alcoholic beverages in the past. The margin of error for this survey is 5%. Find the confidence interval for the proportion.
I have thus far:
p-hat = 0.60
ME= 0.5
CI= 0.60-0.5 < P < 0.60+0.5
CI= 0.1, 1.1
Thank you for assisting.

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
p-hat = 0.60
ME= 0.05 0r 5%
CI= 0.60-0.05 < P < 0.60+0.05
CI = (.55, .65)

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