SOLUTION: P(1)=P(2)=0.2 P(3)=P(4)=0.15 P(5)=0.3 Find the probability of each of the following events: A: { Either 2 or 3 occurs } B: { Either 2, 1, or 4 occurs } C: { 5 does not

Question 913620: P(1)=P(2)=0.2
P(3)=P(4)=0.15
P(5)=0.3
Find the probability of each of the following events:
A: { Either 2 or 3 occurs }
B: { Either 2, 1, or 4 occurs }
C: { 5 does not occur }
P(A)=
P(B)=
P(C)=
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
P(A) = P(2)+P(3)

P(A) = 0.2+0.15

P(A) = 0.35

-------------------------------------------------------

P(B) = P(1)+P(2)+P(4)

P(B) = 0.2+0.2+0.15

P(B) = 0.45

-------------------------------------------------------

P(C) = 1 - P(5)

P(C) = 1 - 0.3

P(C) = 0.7

Let me know if you need more help or if you need me to explain a step in more detail.
Feel free to email me at jim_thompson5910@hotmail.com
or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html

Thanks,

Jim
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