SOLUTION: A jet travels 3065mi against the wind in 5 hours and 3915mi with the wind in the same amount of time. What is the rate of the jet in still air and what is the rate of the wind?

Question 908517: A jet travels 3065mi against the wind in 5 hours and 3915mi
with the wind in the same amount of time. What is the rate of the jet in still air and what is the rate of the wind?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
r*t=d
with the wind
(r+w)*5=3915
(r+w)=3915/5
r+w=783
against the wind
(r-w)*5=3065
(r-w)=3065/5
r-w=613
r+w=783
add
r+r=613+783
2r=1396
r=698
r=698 jet
698-w=613
w=698-613
w=85 wind
check
(698+85)*5=3915
783*5=3915
3915=3915
ok
(r-w)*5=3065
(698-85)*5=3065
613*5=3065
3065=3065
ok

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