SOLUTION: If I have a 52 card deck, there are 4 suits in a deck with 13 of each suit, if I draw out five cards one time what is the probability that all of the five cards will be the same su

Question 903554: If I have a 52 card deck, there are 4 suits in a deck with 13 of each suit, if I draw out five cards one time what is the probability that all of the five cards will be the same suit?
I have attempted this using p=(AnB) * (BnA | AnB) etc
Ending with 5/52 * 4/51 * 3/50 * 2/49 * 1/48
120/375,523,200
I don't think this is correct, I then stumbled upon the equation of
nCr=4*13C5
I do not know if I am even close and would just like to have some help understanding what equation to use or what formula and how to plug in the numbers . I would appreciate any help I could get.
Found 2 solutions by stanbon, Edwin McCravy:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If I have a 52 card deck, there are 4 suits in a deck with 13 of each suit, if I draw out five cards one time what is the probability that all of the five cards will be the same suit?
I have attempted this using p=(AnB) * (BnA | AnB) etc
Ending with 5/52 * 4/51 * 3/50 * 2/49 * 1/48
120/375,523,200
I don't think this is correct, I then stumbled upon the equation of
nCr=4*13C5
I do not know if I am even close and would just like to have some help understanding what equation to use or what formula and how 960960to plug in the numbers . I would appreciate any help I could get.
-----------------------------------------------
Method::
Choose a card suit:: 4 ways
Choose 5 cards from that suit of 13 cards:: 13C5 = 1287
----
So # of ways to succeed = 4*1287 = 5148 ways
-------
# of random sdts of 5 cards = 52C5 = 2598960
======
Ans:: 1287/2598960
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Cheers,
Stan H.
Answer by Edwin McCravy(20054) (Show Source): You can put this solution on YOUR website!

= Edwin

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