SOLUTION: A variable X has a mean of 73.5 and a standard deviation of 61.4. A random sample of size 18 is selected. Assuming X is normally distributed, what is the probability, to two decima

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Question 903081: A variable X has a mean of 73.5 and a standard deviation of 61.4. A random sample of size 18 is selected. Assuming X is normally distributed, what is the probability, to two decimal places, that the sample mean exceeds 100? Give your answer to two decimal places in the form x.xx
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi,

TI syntax is normalcdf(smaller, larger, µ, σ).

Note: The -9999 is used as the smaller value to be at least 5 standard deviations from the mean.

P (x>100) = 1 - P( x≤ 100)  = 1 -  normalcdf(-999, 100, 73.5, 61.4)

 

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