# SOLUTION: how many five-poker hands consisting of the following distribution are there? a- aflush ( all five cards of a signle suit) b- theree of kind (three aces and two other cards) c-

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: how many five-poker hands consisting of the following distribution are there? a- aflush ( all five cards of a signle suit) b- theree of kind (three aces and two other cards) c-       Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Algebra: Probability and statistics Solvers Lessons Answers archive Quiz In Depth

 Question 89947: how many five-poker hands consisting of the following distribution are there? a- aflush ( all five cards of a signle suit) b- theree of kind (three aces and two other cards) c- two pairs ( two aces, two kings and one other card) d- A straight ( all five cards in a sequence)Answer by stanbon(57984)   (Show Source): You can put this solution on YOUR website!how many five-poker hands consisting of the following distribution are there? a- aflush ( all five cards of a signle suit) # of ways to pick a suit = 4 # of ways to get 5 of the 13 cards 13C5 Total # of flush hands = 4*13C5 =================== b- three of kind (three aces and two other cards) # of ways to pick three aces = 4C3 = 4 # of ways to pick two other cards = 48C2 # of ways full house hands = 4*48C2 ----------------------- c- two pairs ( two aces, two kings and one other card) # of ways to pick two aces = 4C2 = 6 # of ways to pick two kings = 4C2 = 6 # of ways to pick one other card = 44C1 = 44 Total # of ways to get 2 aces, 2 kings, one other = 6^2*44 -------------------------------- d- A straight ( all five cards in a sequence) # of ways to get a straight pattern of 5 cards = 9 # of ways to pick the 5 cards 4^5 # of straight hands = 9*4^5 ============== Cheers, Stan H.