Hi
Ho: u ≥ 500
Ha: u < 500
------------------
t(496) = (496-500)/[8/sqrt(20)] = 4/1.7889 = 2.236
--------
p-value = P(t> 2.236 when df = 19) = tcdf(2.236,100,19) = .9825
As .9825 > .10, No, would not conclude mean is <500
ME = 1.645(8/sqrt(25))
CI: = 496 - ME << 496 + ME