SOLUTION: A sample of 25 patients in a doctor's office showed that they had to wait an average of 35 minutes with a standard deviation of 10 minutes before they could see the doctor. Provid
Question 899082: A sample of 25 patients in a doctor's office showed that they had to wait an average of 35 minutes with a standard deviation of 10 minutes before they could see the doctor. Provide a 95% confidence interval estimate for the average waiting time of all the patients who visit this doctor. What is the margin of error? Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Hi
Provide a 95% confidence interval
ME = 1.96[10/sqrt(25)] = 3.92 0r 4
CI: 35 - ME < < 35 + ME
CI z = 1.28155
90% z =1.645
92% z = 1.751
95% z = 1.96 ***
98% z = 2.326
99% z = 2.576