Hi

Ho: p = 0.6 (claim)

Ha: p < 0.4 



sample proportion = p-hat = 110/200= .55

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test stat:: z(0.55) = (0.55-0.6)/sqrt[0.6*0.4/200] = -.05/.0346 = -1.4438

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p-value = P(z < -1.4438) = 0.0744  0r 7.44%

---------------------

Conclusion: 

Since the p-value is greater than 1%, accept Ho.

The test results support the claim.

 

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