SOLUTION: A basket contains 7 green pears and 4 brown pears. One pear is selected at random and is not
replaced. A second pear is then selected at random. What is the probability that the
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Question 893003: A basket contains 7 green pears and 4 brown pears. One pear is selected at random and is not
replaced. A second pear is then selected at random. What is the probability that the first pear is
brown and the second pair is green?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A basket contains 7 green pears and 4 brown pears. One pear is selected at random and is not replaced. A second pear is then selected at random.
What is the probability that the first pear is brown and the second pair is green?
Ans: (4/11)(7/10) = 14/55
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Cheers,
Stan H.
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