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put this solution on YOUR website!1) Find the probability of the result using the normal curve approximation to the binomial distribution. On a hospital floor, 60 patients have a disease with a mortality rate of 0.1. Five of them die.
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The mean is np = (60)(0.1)
The standard dev. = sqrt(npq)
Using a TI caluculator you get normalcdf(4.5,5.5,60*0.1,sqrt(60*0.1*0.9))=0.1555..
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2) Find the probability fo the result using the normal curve approximation to the binomial distribution. A battery company has found that the defective rate of its batteries is 0.03. Each day, 400 batteries are randomly tested. On Tuesday, 14 are found to be defective.
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Mean = 400*0.3
Std = sqrt(400*0.03*0.97)
normalcdf(13.5,14.5,400*0.03,sqrt(400*0.03*0.97)) = 0.09824...
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Cheers,
Stan H.