There are 5 vowels and 21 consonants. (We are considering Y as a consonant). There are C(26,2) = 325 possible pairs of letters. There are C(5,2) = 10 unsuccessful pairs of letters (two vowels) Therefore there are 325-10 = 315 successful pairs of letters. Probability: 315 successful pairs out of 325 possible pairs or, which reduces to . Edwin