SOLUTION: You Explain It! Height of 10-Year-Old Males The heights of 10-year-old males are normally distributed with mean m = 55.9 inches and s = 5.7 inches. (a) Draw a normal curve with

Question 879699: You Explain It! Height of 10-Year-Old Males The heights of 10-year-old males are normally distributed with mean m = 55.9 inches and s = 5.7 inches.
(a) Draw a normal curve with the parameters labeled.
(b) Shade the region that represents the proportion of 10-year-
old males who are less than 46.5 inches tall.
(c) Suppose the area under the normal curve to the left of
x = 46.5 is 0.0496. Provide two interpretations of this result.
I know that is c.) about 5% (4.96%)of kids are under 46.5 inches at 10 years old, or 95% of kids are taller than 46.5 inches. But how do i get answer A and B and how do i graph it ?Thank you

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi

good work on (c). Hope the following is clear to You.

Do recommend stattrek.com as an excellent reference

u = 55.9 and o = 5.7, Normal curve y

y = e^

y = e^

You can put this in a graphing calculator or just sketch it...

They all look the same..just different heights and symmetry about the mean:

locate 46.5 and shade to the left (proportion left of x-value = 46.5)

   .



Do NOT confuse this with the 'standard normal curve' using z-values..

where left of z-value = (46.5-55.9)/5.9 = -1.649 (proportion left of x-value = 46.5)

Note: P(z < -1.649) = .0496

For the normal distribution: Below:  z = 0, z = � 1, z= �2 , z= �3 are plotted.  

Area under the standard normal curve to the left of the particular z is P(z)

Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50%  to the right



 

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