SOLUTION: In a recent poll 73% of 3011 adult surveyed said they use the Internet. construct a 98% confidence interval for the proportion of all adults use the Internet
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Question 875405
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In a recent poll 73% of 3011 adult surveyed said they use the Internet. construct a 98% confidence interval for the proportion of all adults use the Internet
Answer by
ewatrrr(24785)
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Hi
ME(In %) = z*sqrt(pq/n) =
= .019 0r 2%
CI: 73%-ME < u < 73% + ME
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