SOLUTION: suppose a normal distribution has a mean of 38 and a standard deviation of 2. what is the probability that a data value is between 37 and 41 rounded to the nearest tenth percent

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Question 873276: suppose a normal distribution has a mean of 38 and a standard deviation of 2. what is the probability that a data value is between 37 and 41 rounded to the nearest tenth percent
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi

P(z ≤ 1.5) - P(z ≤ -.5) = .9332 - .3085 0r normalcdf(37,41,38,2) =  .6247 

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