SOLUTION: If 49% of the people at a certain conference are doctors,40% are women, and 76% are doctors or women (or both), what is the probability that a person selected at random at this con

SOLUTION: If 49% of the people at a certain conference are doctors,40% are women, and 76% are doctors or women (or both), what is the probability that a person selected at random at this con

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Question 872445: If 49% of the people at a certain conference are doctors,40% are women, and 76% are doctors or women (or both), what is the probability that a person selected at random at this conference is a female doctor? how do i do this type of problem im stuck
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
.76 = .49 + .40 - .13
(Dr 0r women) = Dr + W - B
Female Doctor = 13%
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