SOLUTION: A random sample of 200 students at UCLA shows that 120 of them have internet access. Test the claim that the true population proportion of students at UCLA who have internet acce

Question 871840: A random sample of 200 students at UCLA shows that 120 of them have internet access. Test the claim that
the true population proportion of students at UCLA who have internet access is more than 55%. Use 3% level of
significance. Use the P-Value method.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A random sample of 200 students at UCLA shows that 120 of them have internet access.
Test the claim that the true population proportion of students at UCLA who have internet access is more than 55%.
Use 3% level of significance. Use the P-Value method.
--------
Ho: p <= 0.55
Ha: p > 0.55 (claim)
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test statistic:: z(120/200) = (0.6-0.55)/sqrt[0.55*0.45/200] = 1.4213
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p-value = P(z > 1.4213) = normalcdf(1.4213,100) = 0.078
-----
Conclusion:: Since the p-value is greater than 3%, fail to reject Ho.
Conclusion:: The test results do no support the claim.
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Cheers,
Stan H.
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