SOLUTION: A company claimed to randomly choose a committee of three employees to represent the employees at a bargaining session. Of the 50 employees from whom the committee was chosen, 20

Question 870014: A company claimed to randomly choose a committee of three employees to represent the employees at a bargaining session. Of the 50 employees from whom the committee was chosen, 20 are female and 30 are male. The committee turned out to be all male.
Determine the probability the committee of three would include at least one female, if the selection were truly random.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
The probability that the committee of 3 would consist of all 3 men is equal to:

30/50 * 29/49 * 28/48 = .2071

The probability that at least one of the committee members would be female is equal to:

1 - .2071 = .7929

round these answers to 2 decimal places and you get:

p(all males) = .21
p(at least 1 female) = .79

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