SOLUTION: Two events, E and F, are such that P(E)=2/5, P(F)=1/6 and P(E U F)=13/30. Show that E and F are neither mutually exclusive nor independent. I'm honestly not even sure what it's

Question 868492: Two events, E and F, are such that P(E)=2/5, P(F)=1/6 and P(E U F)=13/30. Show that E and F are neither mutually exclusive nor independent.
I'm honestly not even sure what it's asking me to do, does it want me to prove that it's not mutually exclusive by calculating if it is mutually exclusive? I'm quite lost with this problem..
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
If they were mutually exclusive, then
and
Like a coin can't land heads and tails, it can only land heads or tails.
.
.
.
Independent events follow this rule,

In this case,

False, so E and F are not independent either.
As an example, the probability of flipping a coin twice and getting a head and then a tail is,

Proves that coin flipping is independent, your second flip doesn't depend on what you got on the first flip.

RELATED QUESTIONS
E and F are mutually exclusive events. P(E) = 0.15; P(F) = 0.71. Find P(E | F) (answered by greenestamps,Edwin McCravy)

E and F are mutually exclusive events. P(E) = 0.15; P(F) = 0.71. Find P(E | F) (answered by ikleyn)

Given that E and F are mutually exclusive events with the P(E) = 0.3 and the P(F) = 0.6,... (answered by stanbon)

Let P(E)=0.25 and P(F)=0.45 1. Find P(E and F) if P(E or F)=0.6 2. Find P(E and F) if E (answered by stanbon)

Suppose that E and F are two events and that P(E)=0.4 and P(F|E)=0.5. What is P(E and... (answered by MathLover1)

Suppose that E and F are two events and that P(E and F)=0.1 and P(E)=0.2. What is P(F/E)? (answered by jim_thompson5910)

Suppose that E and F are two events and that P(E and F)=0.5 and P(E)=0.8 What is P(F|E)... (answered by Glaviolette)

suppose that e and f are two events and that p(e)=0.2 and p(f|e)=0.4. what is p(e and f)? (answered by Theo)

suppose that E and F are two events and that P(e and f)=0.2 and P(e)=0.5. What is... (answered by ikleyn)