SOLUTION: I need help with these three problems.
Problem #1
Find probablity
when a single card is drawn from a wll-shuffled 52-card deck, find the probability of getting a club.
Prob
Algebra.Com
Question 86723: I need help with these three problems.
Problem #1
Find probablity
when a single card is drawn from a wll-shuffled 52-card deck, find the probability of getting a club.
Problem #2
Find probability
Each of ten tickets is marked with a different number from 1-10 and put in a box. If you draw a ticket at random from the box, what is the probability that you will draw 4,8,or 6?
Problem #3
Find probability
Suppose one card is selected at random from an ordinary deck of 52 playing cards.
Letting:
A = event a queen is selected
B = event a diamond is selected
Answer by tanimachatterjee(60) (Show Source): You can put this solution on YOUR website!
See here we have well shuffled 52 card deck and we have to drawn one single card .There are 13 clubs in 52 card deck. we know that let a space of elementary events E be given and this space consists of N equally likely elementary events, among which there are n events, favorable for an event A. Then the number
Р ( А ) = n / N
is called the probability of an event A .
here n = 13( from 13 clubs we have to pick 1 club)
and N= 52 ( from 52 cards we are picking 1 )
required probability = 13/52 = 1/4(Answer)
Each of ten tickets is marked with a different number from 1-10 and put in a box. If you draw a ticket at random from the box, what is the probability that you will draw 4,8,or 6?
See here n=3 (4 or 8 or 6, from these 3 we are picking 1)
and N = 10(total no. of 10 tickets we are picking 1)
so reqd probability = 3/10(Answer)
from an ordinary deck of 52 playing cards.
Letting:
A = event a queen is selected
B = event a diamond is selected
Here reqd probability = 4/52=1/13
total no. of queen =4
and total no. of diamond = 13
so reqd probability = 13/52 = 1/4
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