SOLUTION: please help me solve this problem. The combined math verbal scores for students taking a national standardized examination for college, is normally distributed with a mean of 53

Question 866773: please help me solve this problem.
The combined math verbal scores for students taking a national standardized examination for college, is normally distributed with a mean of 530 and a standard deviation of 180. If a college requires a minimum of 1000 for admission, what percentage of student do not satisfy that requirement?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
mean is 530
standard deviation is 180
z-score for this test is:
z = (1000 - 530) / 180
you get:
z = 2.611111
round this off to 2.61 because the z-score tables only go to 2 decimal places.
look that z-score up in the z-score table and you will see that the area to the left of that z-score in the table is equal to .9955. this means that 99.55% of the students would not be able to pass the minimum requirements for admission to that school.
the z-score table is can be found at the following link:
http://lilt.ilstu.edu/dasacke/eco148/ztable.htm
scroll down the left column until you reach 2.6.
scroll to the right on that row until you reach the column with the heading of .01.
the number shown should be equal to .9955
that number is in the second column to the right of the first column.
in this particular table, the number shown is the area to the left of the indicated z-score.
multiply that number by 100 and that number is telling you the percent of the population that has a z-score less than the indicated z-score.
a z-score less than 2.61 means a raw score less than 1000 in this problem.

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