SOLUTION: The population of the scores of all high school seniors that took the SAT-M test (mathematics component of the SAT test) last year followed a Normal distribution, with mean mu and

Question 866629: The population of the scores of all high school seniors that took the SAT-M test (mathematics component of the SAT test) last year followed a Normal distribution, with mean mu and standard deviation = 100. You read a report that says, �On the basis of a simple random sample of 500 high school seniors that took the SAT-M test this year, a confidence interval for the population (mu) is 512.00 � 11.52.�
A 95% confidence interval for the population (mu) would be
Question 4 options:

503.24 to 520.77

500.48 to 523.52

316 to 708

None of the above

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The lower bound L and the upper bound U are equal to

L = xbar - ME
U = xbar + ME

where xbar is the sample mean and ME is the margin of error. In this case,

xbar = 512
ME = 11.52

These are both given when they report the confidence interval (CI) of 512.00 � 11.52

So,

L = xbar - ME
L = 512 - 11.52
L = 500.48

and

U = xbar + ME
U = 512 + 11.52
U = 523.52

Making the final answer to be 500.48 to 523.52
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