Hi
mean of 318 mg of sodium, and the standard deviation is 32 mg.
n = 60
a) SE = 32/sqrt(60)= 4.1312
b) ME = 1.96(4.1312) = 8
CI: 318-8 < u < 318 + 8 (310, 336)
c) .7(465) = 325.5, Yes reduced. It is in the confidence Interval
CI z -value
90% z =1.645
92% z = 1.751
95% z = 1.96
98% z = 2.326
99% z = 2.576