SOLUTION: In a survey of 2480 golfers, 15% said they were left-handed. The survey margin of error was 3%. Construct a confidences interval for the proportion do the left handed golfers?

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Question 866028: In a survey of 2480 golfers, 15% said they were left-handed. The survey margin of error was 3%. Construct a confidences interval for the proportion do the left handed golfers?
Please help I don't even know how to start to solve it!

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
15% said they were left-handed. ME = 3%.
CI: p-ME < p < p + ME
Ci: 12% < p < 18%

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