SOLUTION: An airline has room for 262 passengers. Because some people do not show up, the airline books 290 people on the flight. If the mean number of "No Shows" is 45 people with a std. de

Question 865468: An airline has room for 262 passengers. Because some people do not show up, the airline books 290 people on the flight. If the mean number of "No Shows" is 45 people with a std. deviation of 10, what percentage of these flights will be unable to seat all passengers who do show up?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi

mean number of "No Shows" is 45 people with a std. deviation of 10,

290-262 = 28

z = |(28-45)/10| = 1.7

P(z > 1.7)= 4.46% 

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