Hi
4 earrings: 2G, 2S
P(2S) =
This problem was posted over a decade ago (2014) and solved by a nice lady tutor back then whose screen name was ewatrrr(24785). Notice she has solved it correctly. She is thinking of your randomly choosing them one at a time. The probability of your successfully choosing a silver earring the first time is 2 out of 4, or (2/4). If you are successful on the first choice, then there are 3 earrings left in the box, the other silver one, and the 2 gold ones. The probability is then 1 out of 3 (1/3) of drawing the other silver earring. Therefore the desired probability is, as she so correctly gives,. Edwin
Ikleyn has apologized. I accept her apology whole-heartedly. I have no doubt she is a good-hearted person. We all get frustrated sometimes. We can't help our emotional feelings. We all feel a little narcistic and feel like bullying at times. But the best way is always to keep our emotional feelings, as they say, 'in check!'. There is no such thing as "thinking you ARE wrong". There is only "thinking that you WERE wrong". We always think we're right until we discover our error and somebody shows us where our thinking is going astray. Then we are embarrassed. But that's what we get for being humans!! BTW, who do you think might have posted that problem about the red and green balls? I'll never tell! J Edwin