SOLUTION: In a binomial distrubution, the probability of 25 successes, where n=65 and p=0.35 is..
A. C(65,25)(o.35)^25 (o.15)^40
B. C(65,25)(0.35)^25 (0.65)^40
C. C(65,25)(0.35)^40
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-> SOLUTION: In a binomial distrubution, the probability of 25 successes, where n=65 and p=0.35 is..
A. C(65,25)(o.35)^25 (o.15)^40
B. C(65,25)(0.35)^25 (0.65)^40
C. C(65,25)(0.35)^40
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Question 86398: In a binomial distrubution, the probability of 25 successes, where n=65 and p=0.35 is..
A. C(65,25)(o.35)^25 (o.15)^40
B. C(65,25)(0.35)^25 (0.65)^40
C. C(65,25)(0.35)^40 (0.65)^25
D. C(65,25)(0.35)^25 Answer by stanbon(75887) (Show Source):
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