Hi
a)with z = (344-183)/31 = 5.1935....
how many times would you expect there to be more passengers than available seats? never
b) $71000/$460 = 154
z = (154-183)/31 = - .9243
P(z<-.9245) = 17.77% of the time
c) .1777*12 = 2.1324 Approximately 2 days
my thoughts...
Wish You the Best in your Studies.