SOLUTION: What proportion of members spend less than 40 minutes at the gym?given a mean of 80 minutes and standard deviation of 20

Question 862576: What proportion of members spend less than 40 minutes at the gym?given a mean of 80 minutes and standard deviation of 20
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi

mean of 80 minutes and standard deviation of 20

P( x< 40) = P(z < (40-80)/20 ) = P(z < -2)   invNorm(-2) = .0228  0r 2.28% 

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