SOLUTION: in a gallup poll, 1025 randomly selected adults were surveyed and 29% of them said that they used the internet for shopping at least twice a year. a)find the point estimate of th

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Question 861790: in a gallup poll, 1025 randomly selected adults were surveyed and 29% of them said that they used the internet for shopping at least twice a year.
a)find the point estimate of the percentage of adults who use the internet for shopping?
b)Find a 99% confidence interval estimate of the percentage of adults who use the internet for shopping?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi,

a) for P(x ≥ 2) TI syntax is 1 – binomcdf(n, p, largest x-value).

P(x ≥ 2) = 1 - binomcdf(1025,.29,1)

b)  = 297.25 is the mean

ME = 

CI: 297.25-ME < u < 297.25 + ME





CI	z -value

90%	z =1.645

92%	z = 1.751

95%	z = 1.96

98%	z = 2.326

99%	z = 2.576



 

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